Question

К потолку подвешены два маятника,за одинаковое время,один маятник совершил 5 колебаний,а другой -3 колебания.Какова длина каждого маятника,если разность их длин равна 48 см?............ помогите пожалуйста!

Answer 1

Не знаю 176 ц3с67мсяч н7мчяс

Answer 2

Problem Analysis

We are given two pendulums hanging from the ceiling. One pendulum completes 5 oscillations in a certain time, while the other completes 3 oscillations in the same time. We need to find the length of each pendulum given that the difference in their lengths is 48 cm.

Solution

Let's assume the length of the first pendulum is L1 and the length of the second pendulum is L2.

We know that the time period of a pendulum is given by the formula:

T = 2π√(L/g)

where: - T is the time period of the pendulum, - L is the length of the pendulum, and - g is the acceleration due to gravity.

Since both pendulums complete their oscillations in the same time, we can equate their time periods:

T1 = T2

Substituting the formula for time period, we get:

2π√(L1/g) = 2π√(L2/g)

Simplifying, we get:

√(L1/g) = √(L2/g)

Squaring both sides, we get:

L1/g = L2/g

Simplifying further, we get:

L1 = L2

This means that the lengths of both pendulums are equal.

Now, we are given that the difference in their lengths is 48 cm:

L1 - L2 = 48

Since we know that L1 = L2, we can substitute this value:

L1 - L1 = 48

Simplifying, we get:

0 = 48

This equation is not possible, which means there is no solution to this problem. The given information is contradictory.

Therefore, it is not possible to determine the length of each pendulum given the information provided.

Please let me know if there is anything else I can help you with.