Question

Шарик вылетает из детского пружинного пистолета вертикально вверх с начальной скоростью 5м/с. На какую высоту от места вылета он поднимется?

Answer 1

H=2V^2/2gб т.е H=25/20=1,25 м

Answer 2

Calculating the Maximum Height Reached by the Ball

To calculate the maximum height reached by the ball, we can use the following kinematic equation:

v_f^2 = v_i^2 + 2 * a * d

Where: - v_f = final velocity (0 m/s at the maximum height) - v_i = initial velocity (5 m/s) - a = acceleration due to gravity (-9.81 m/s^2, considering the direction) - d = displacement (the maximum height)

Calculation

Using the given initial velocity of 5 m/s and the acceleration due to gravity of -9.81 m/s^2, we can calculate the maximum height reached by the ball using the kinematic equation.

v_f^2 = v_i^2 + 2 * a * d

Rearranging the equation to solve for d (the maximum height): d = (v_f^2 - v_i^2) / (2 * a)

Substituting the given values: d = (0 - 5^2) / (2 * (-9.81))

Calculating: d ≈ 1.28 meters

Conclusion

The ball will reach a maximum height of approximately 1.28 meters from the point of launch.