
R1 = 10 OмR2 = 15 OмR3 = 25 OмR-?


Ответы на вопрос

Ответ:
R=10 Om×15 Om×25 Om/(10 Om×15 Om)+(15 Om×25 Om)+(10 Om×25 Om)=4,8



It seems like you want to calculate the equivalent resistance (Req) of a combination of resistors R1, R2, and R3. To calculate the equivalent resistance, you need to know the arrangement of these resistors, whether they are connected in series or in parallel.
If the resistors are in series: In a series circuit, the equivalent resistance is the sum of the individual resistances. Req = R1 + R2 + R3 Req = 10 Ω + 15 Ω + 25 Ω Req = 50 Ω
If the resistors are in parallel: In a parallel circuit, the reciprocal of the equivalent resistance is the sum of the reciprocals of the individual resistances. 1/Req = 1/R1 + 1/R2 + 1/R3 1/Req = 1/10 Ω + 1/15 Ω + 1/25 Ω 1/Req ≈ 0.1 + 0.0667 + 0.04 1/Req ≈ 0.2067 Req ≈ 1 / 0.2067 Req ≈ 4.834 Ω
Without knowing the specific arrangement (series or parallel) of the resistors, I can't provide a definite value for the equivalent resistance. Please provide more information about how the resistors are connected so that I can help you calculate the equivalent resistance accurately.


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