Question

Тіло масою 3 кг вільно падає з висоти 30м. Знайти його кінетичну енергію після перших двох секунд падіння.

Answer 1

Ответ:

Енергія буде 5858675м ❤️❤️❤️❤️❤️❤️❤️❤️❤️

Answer 2

Problem Analysis

We are given the mass of an object (3 kg) and the height from which it falls (30 m). We need to find its kinetic energy after the first two seconds of falling.

Solution

To find the kinetic energy of the object, we need to use the formula:

Kinetic Energy = (1/2) * mass * velocity^2

To find the velocity of the object after two seconds of falling, we can use the equation of motion:

velocity = initial velocity + acceleration * time

Since the object is falling freely, the acceleration due to gravity can be considered as 9.8 m/s^2.

Let's calculate the velocity after two seconds and then find the kinetic energy.

Calculation

Given: - Mass of the object (m) = 3 kg - Height from which it falls (h) = 30 m - Time (t) = 2 seconds - Acceleration due to gravity (g) = 9.8 m/s^2

Using the equation of motion, we can find the velocity after two seconds:

velocity = initial velocity + acceleration * time

Since the object is initially at rest, the initial velocity is 0 m/s:

velocity = 0 + 9.8 * 2

velocity = 19.6 m/s

Now, we can calculate the kinetic energy using the formula:

Kinetic Energy = (1/2) * mass * velocity^2

Kinetic Energy = (1/2) * 3 * (19.6)^2

Kinetic Energy = 0.5 * 3 * 384.16

Kinetic Energy = 576.24 Joules

Therefore, the kinetic energy of the object after the first two seconds of falling is 576.24 Joules.

Conclusion

The kinetic energy of the object after the first two seconds of falling from a height of 30 meters is 576.24 Joules.