Question

Який тиск чинить на рейку чотиривісний вагон масою 68т, якщо площа стикання одного колеса з рейкою 8,5 см2​

Answer 1

p=F/S=mg/4S

p=68 000*10/4*8,5*10^-4=200 000 000 (Па)

Answer 2

Calculating Pressure Exerted by a Four-Wheeled Wagon

To calculate the pressure exerted by a four-wheeled wagon with a mass of 68 tons and a wheel contact area of 8.5 cm², we can use the formula for pressure:

Pressure (P) = Force (F) / Area (A)

Where: - Force (F) = Weight of the wagon - Area (A) = Wheel contact area

First, let's convert the mass of the wagon from tons to kilograms: 1 ton = 1000 kilograms

So, 68 tons = 68,000 kilograms.

Now, we can calculate the force exerted by the wagon: Force (F) = Mass (m) x Acceleration due to gravity (g)

The acceleration due to gravity, g, is approximately 9.81 m/s².

Force (F) = 68,000 kg x 9.81 m/s²

Let's calculate the force.

Force (F) = 666,480 N

Now, we can calculate the pressure exerted by the wagon on the rail using the given wheel contact area of 8.5 cm².

Pressure (P) = 666,480 N / 8.5 cm²

Before proceeding, we need to convert the wheel contact area from cm² to m²: 1 cm² = 0.0001 m²

So, 8.5 cm² = 8.5 x 0.0001 m² = 0.00085 m²

Now, we can calculate the pressure.

Pressure (P) = 666,480 N / 0.00085 m²

Let's calculate the pressure.

Pressure (P) ≈ 784,141,176.47 Pa

Therefore, the pressure exerted by the four-wheeled wagon with a mass of 68 tons and a wheel contact area of 8.5 cm² is approximately 784,141,176.47 Pascals.