Question

Представь, что Нева вышла из берегов и затопила памятник Петру I (Медный всадник). Известно, что его масса равна 88 т, а отлит он из бронзы. Рассчитай в Н силу Архимеда, действующую на утонувший памятник. Плотность бронзы прими равной 87008700 кг/м^3 3 .Запиши в поле ответа число, округлив до целых.​

Answer 1

если не верно,извини .....

Answer 2

Calculation of the Archimedes' Force on the Sunken Monument

To calculate the Archimedes' force acting on the sunken monument, we need to use the formula:

Archimedes' Force = Density of Fluid x Volume of Displaced Fluid x Acceleration due to Gravity

In this case, the fluid is water, and the volume of displaced fluid is equal to the volume of the monument.

1. Calculation of the Volume of the Monument: - The mass of the monument is given as 88 tons, which is equal to 88,000 kg. - The density of bronze is given as 8700 kg/m^3. - Using the formula Density = Mass / Volume, we can rearrange it to find the volume: ``` Volume = Mass / Density ``` - Substituting the given values, we get: ``` Volume = 88,000 kg / 8700 kg/m^3 ``` - Calculating this, we find that the volume of the monument is approximately 10.1149 m^3.

2. Calculation of the Archimedes' Force: - The density of water is approximately 1000 kg/m^3. - The acceleration due to gravity is approximately 9.8 m/s^2. - Using the formula mentioned earlier, we can calculate the Archimedes' force: ``` Archimedes' Force = Density of Fluid x Volume of Displaced Fluid x Acceleration due to Gravity ``` - Substituting the given values, we get: ``` Archimedes' Force = 1000 kg/m^3 x 10.1149 m^3 x 9.8 m/s^2 ``` - Calculating this, we find that the Archimedes' force acting on the sunken monument is approximately 99,000 N.

Therefore, the Archimedes' force acting on the sunken monument is approximately 99,000 N.