Question

Прямой провод массой 200 г. в магнитном поле В = 2 Тл подвешен на нитях. Найти силу натяжения каждой нити. Сила тока равна 1 А, длина провода 0,3 м. *

Answer 1

Ответ:

1,3 Н

Объяснение:

На проводник действуют сила Ампера FА, сила тяжести mg и сила натяжения каждой нити Т.

. Сила Ампера FА направленная вертикально вниз, равна FA= IBL. Условие равновесия сил, действующих на проводник, имеет вид:

2Т =mg+FA

Тогда Т = (mg+FA)/2

Т = (mg+IBL)/2

Т = (0,2*10+1*2*0,3)/2 = 1,3 Н

Answer 2

Problem Statement

You have a straight wire with a mass of 200 g hanging on threads in a magnetic field with a magnitude of 2 T. The wire has a current of 1 A and a length of 0.3 m. You need to find the tension force in each thread.

Solution

To find the tension force in each thread, we can use the formula for the magnetic force on a current-carrying wire in a magnetic field:

F = BIL

Where: - F is the force on the wire, - B is the magnetic field strength, - I is the current flowing through the wire, and - L is the length of the wire.

In this case, the force on the wire is equal to the tension force in each thread. Let's calculate it step by step.

1. Convert the mass of the wire to kilograms: - Mass = 200 g = 0.2 kg

2. Calculate the force on the wire using the formula: - F = BIL - F = (2 T)(1 A)(0.3 m) - F = 0.6 N

3. Divide the force by the number of threads to find the tension force in each thread: - Tension force in each thread = Force / Number of threads

Since the number of threads is not provided in the question, we cannot calculate the exact tension force without that information. Please provide the number of threads, and I will be able to give you the final answer.

Let me know if you need any further assistance!