Question

(2а-11)(11+2а)-(2а-5)^2=2а-146ПОМОГИТЕ ПЖЛ ДАЮ 20БАЛЛЛЛООООВВВ​

Answer 1

To solve the equation (2a-11)(11+2a)-(2a-5)^2=2a-146, we can follow these steps:

1. Expand the terms on both sides of the equation: (2a-11)(11+2a) - (2a-5)^2 = 2a - 146

Expanding the left side: (2a)(11) + (2a)(2a) - (11)(11) - (11)(2a) - (2a)(5) + (5)(5) = 2a - 146

Simplifying the left side: 22a + 4a^2 - 121 - 22a - 10a + 25 = 2a - 146

2. Combine like terms on both sides of the equation: 4a^2 - 121 - 10a + 25 = 2a - 146

Simplifying the equation: 4a^2 - 10a - 121 + 25 = 2a - 146

Combining like terms: 4a^2 - 10a - 96 = 2a - 146

3. Move all terms to one side of the equation: 4a^2 - 10a - 2a + 96 + 146 = 0

Simplifying the equation: 4a^2 - 12a + 242 = 0

4. Solve the quadratic equation: To solve the quadratic equation, we can use the quadratic formula: a = (-b ± √(b^2 - 4ac)) / (2a).

In this case, a = 4, b = -12, and c = 242.

Plugging these values into the quadratic formula: a = (-(-12) ± √((-12)^2 - 4(4)(242))) / (2(4))

Simplifying: a = (12 ± √(144 - 3872)) / 8

a = (12 ± √(-3728)) / 8

Since the discriminant (b^2 - 4ac) is negative, the quadratic equation has no real solutions. Therefore, there is no value of 'a' that satisfies the equation (2a-11)(11+2a)-(2a-5)^2=2a-146.

Please let me know if there's anything else I can help you with!