
Вопрос задан 07.09.2020 в 04:04.
Предмет Математика.
Спрашивает Малая Севиль.
У Бобика было в 8 раз больше колбасы, чем у Тузика. (Ура!!! Они вернулись !!!! ) Когда Бобик
съел 210г своей колбасы, а Тузик украл у хозяина еще 730г колбасы, у них стало колбасы поровну. Сколько было вначале у каждого?

Ответы на вопрос

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Problem Analysis
We are given that Bobik had 8 times more sausage than Tuzik. After Bobik ate 210g of his sausage and Tuzik stole an additional 730g of sausage from the owner, they had an equal amount of sausage. We need to determine how much sausage each of them had initially.Solution
Let's assume that Tuzik had x grams of sausage initially. According to the given information, Bobik had 8 times more sausage than Tuzik, so Bobik had 8x grams of sausage initially.After Bobik ate 210g of his sausage, he had 8x - 210g of sausage left. Tuzik, on the other hand, stole an additional 730g of sausage, so he had x + 730g of sausage.
We are told that after these events, Bobik and Tuzik had an equal amount of sausage. Therefore, we can set up the following equation:
8x - 210g = x + 730g
Simplifying the equation, we get:
7x = 940g
Dividing both sides of the equation by 7, we find:
x = 940g / 7 = 134.29g (rounded to two decimal places)
So, Tuzik initially had approximately 134.29 grams of sausage, and since Bobik had 8 times more sausage, he initially had approximately 8 * 134.29 = 1074.32 grams of sausage.
Answer
Initially, Bobik had approximately 1074.32 grams of sausage, and Tuzik had approximately 134.29 grams of sausage.

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