Question

Посыльный катер преодолел расстояние от Североморска до плавбазы подлодок за 8 ч со скоростью 30 км/ч. На обратном пути то же расстояние катер прошел за 6 ч . Какова скорость катера на обратном пути? (Ответ: 40 км/ч) пед.колледж.-_-

Answer 1

Problem Analysis

We are given that a mail boat (посыльный катер) traveled from Severomorsk to a submarine base at a speed of 30 km/h and took 8 hours. On the return trip, it covered the same distance in 6 hours. We need to determine the speed of the boat on the return trip.

Solution

Let's assume the distance between Severomorsk and the submarine base is D km.

On the forward trip, the boat traveled at a speed of 30 km/h and took 8 hours. Therefore, we can write the equation:

D = 30 * 8 [[1]]

On the return trip, the boat covered the same distance in 6 hours. Let's denote the speed of the boat on the return trip as S km/h. We can write the equation:

D = S * 6 [[2]]

Since both equations represent the same distance, we can equate them:

30 * 8 = S * 6

Simplifying the equation, we find:

S = (30 * 8) / 6

Evaluating the expression, we get:

S = 40 km/h

Therefore, the speed of the boat on the return trip is 40 km/h.

Answer

The speed of the mail boat on the return trip is 40 km/h.