Question

Стороны паралелограмма равны 8 и 16 см, один из углов равен 60градусов, найти высоту проведенную к стороне равной 16 см

Answer 1

Sin 60°=AM(висота)/AD
AM=sin 60°*AD=8*√3/2= 4√3

Answer 2

Given Information

We are given that the sides of the parallelogram are 8 cm and 16 cm, and one of the angles is 60 degrees. We need to find the height drawn to the side that is 16 cm long.

Solution

To find the height drawn to the side that is 16 cm long, we can use the formula for the area of a parallelogram:

Area = base * height

In this case, the base is 16 cm, and we need to find the height. Let's denote the height as 'h'.

Area = 16 cm * h

To find the area, we can use the formula:

Area = (1/2) * a * b * sin(C)

where 'a' and 'b' are the lengths of the sides of the parallelogram, and 'C' is the angle between them.

In this case, 'a' is 8 cm, 'b' is 16 cm, and 'C' is 60 degrees.

Area = (1/2) * 8 cm * 16 cm * sin(60 degrees)

Now we can substitute the values and calculate the area.

Area = (1/2) * 8 cm * 16 cm * sin(60 degrees) = 64 cm^2 * sqrt(3) / 2

Since the area is equal to the base times the height, we can set up the equation:

64 cm^2 * sqrt(3) / 2 = 16 cm * h

Simplifying the equation, we get:

32 cm^2 * sqrt(3) = 16 cm * h

Dividing both sides by 16 cm, we get:

2 cm * sqrt(3) = h

Therefore, the height drawn to the side that is 16 cm long is 2 cm * sqrt(3).

Answer

The height drawn to the side that is 16 cm long is 2 cm * sqrt(3).