Question

Помогите решить ! Срочно !

Answer 1

$(\frac{1}{7})^{2x-1}=49 \\ (\frac{1}{7})^{2x-1}=(\frac{1}{7})^{-2} \\ 2x-1=-2 \\ 2x=-1 \\ x=-0.5$

Answer 2

(1/7)^2х-1=(1/7)^-2

2х-1=-2

2х=-1

х=-0.5