Question

Вопрос 1 из двух деревень одновременно навстречу друг-другу выехали два велосипедиста . Скорость одного из них 14,4 км/ч а скорость второго составляет 2\3 скорости первого .найди расстояние между деревнями если велосипедисты встретились через 42 минуты

Answer 1

14,4*2/3=9,6км/час скорость второго
14,4+9,6=24км/час скорость сближения
42мин=42/60=0,7 часа
24*0,7=16,8км расстояние

Answer 2

Problem Analysis

We are given that two cyclists start simultaneously from two different villages and are heading towards each other. The speed of one cyclist is 14.4 km/h, while the speed of the other cyclist is 2/3 of the speed of the first cyclist. We need to find the distance between the villages if the cyclists meet after 42 minutes.

Solution

Let's denote the speed of the first cyclist as v1 and the speed of the second cyclist as v2. We are given that v1 = 14.4 km/h and v2 = 2/3 * v1.

To find the distance between the villages, we can use the formula distance = speed * time. Since the cyclists are moving towards each other, their combined speed is v1 + v2.

We are given that the cyclists meet after 42 minutes, which is equal to 42/60 = 0.7 hours.

Using the formula distance = speed * time, we can calculate the distance between the villages as:

distance = (v1 + v2) * time

Substituting the values of v1, v2, and time, we get:

distance = (14.4 + 2/3 * 14.4) * 0.7

Let's calculate the distance.