Question

Реши задачу. Из улья вылетела пчела и полетела со скоростью 8 м/с. Через 30 с вслед за ней вылетела вторая пчела и полетела со скоростью 9 м/с. Через какое время вторая пчела догонит первую?

Answer 1

Возьмём за X время которое пролетит первая пчеле до того
как они встретятся следовательно время полёта второй пчелы X-30
уравнение будет выглядеть так
8Х = 9(Х-30)
далее 9Х - 8Х = 270 или Х = 270 или 4 минуты 30 секунд

Answer 2

Problem Analysis

We are given that a bee flies out of the hive with a speed of 8 m/s, and after 30 seconds, another bee flies out with a speed of 9 m/s. We need to determine how long it will take for the second bee to catch up to the first bee.

Solution

Let's assume that the time it takes for the second bee to catch up to the first bee is t seconds.

During the first 30 seconds, the first bee has already covered a distance of 8 m/s * 30 s = 240 meters.

Now, let's consider the time t after the second bee starts flying. At this point, the first bee has already covered a distance of 8 m/s * t meters, and the second bee has covered a distance of 9 m/s * t meters.

For the second bee to catch up to the first bee, the distance covered by the second bee must be equal to the distance covered by the first bee plus the initial distance between them (240 meters).

Therefore, we can set up the following equation:

9 m/s * t = 8 m/s * t + 240 meters

Simplifying the equation, we get:

t = 240 meters / (9 m/s - 8 m/s)

t = 240 seconds

Answer

The second bee will catch up to the first bee after 240 seconds.

Please let me know if I can help you with anything else.