Question

(4x-1)^2=помогите пожалуйста!

Answer 1

2,4x - 1,26 / (1/2-1/3) = 1,3x-0,5 / (1/10-1/9)2,4x-1,26/0,5-0,3=1,3x-0,5/0,1-0,12,4x-1,26-1,3x-0,5/0,5-0,32,4x-4,2-1,3x=02,4x-1,3x=4,21,1x=4,2x=3,1

Answer 2

Problem Statement

The equation (4x-1)^2 is given. We need to solve this equation.

Solution

To solve the equation (4x-1)^2, we can expand the square and then solve for x.

Expanding the square, we get:

(4x-1)^2 = (4x-1)(4x-1)

Using the FOIL method (First, Outer, Inner, Last), we can multiply the terms:

(4x-1)(4x-1) = 16x^2 - 4x - 4x + 1

Simplifying further, we have:

16x^2 - 8x + 1

Now, we have a quadratic equation in the form ax^2 + bx + c = 0, where a = 16, b = -8, and c = 1.

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values of a, b, and c, we get:

x = (-(-8) ± √((-8)^2 - 4(16)(1))) / (2(16))

Simplifying further, we have:

x = (8 ± √(64 - 64)) / 32

x = (8 ± √0) / 32

Since the discriminant (√(b^2 - 4ac)) is 0, the quadratic equation has a single real root.

Therefore, the solution to the equation (4x-1)^2 is:

x = 1/4

Answer

The solution to the equation (4x-1)^2 is x = 1/4.