Question

Воспитывая своего сына двоечника папа изнашивает в год 2 брючных ремня. Сколько ремней износил папа за все одиннадцать лет учебы, если известно, что в 5 классе его сын дважды оставался на второй год?

Answer 1

1) 11+2=13 лет всего учился сын
2) 13*2=26 ремня износил папа за 12 лет

Answer 2

1) 11+2=13 (кл) - учился сын.

2)13*2= 26(р) 

ответ: 26 ремня износил папа. 

Answer 3

Calculation of the Number of Belts Worn Out by the Father

To calculate the number of belts worn out by the father over the course of eleven years of his son's education, we need to consider the information provided in the question.

According to the question, the father wears out 2 belts per year while raising his son, who is a "двоечник" (a student who consistently receives a grade of "2" in school). Additionally, it is mentioned that the son repeated the second grade twice.

To calculate the total number of belts worn out by the father, we need to consider the following:

1. The father wears out 2 belts per year. 2. The son repeated the second grade twice.

Let's break down the calculation step by step:

1. Calculate the number of belts worn out by the father for the years when the son did not repeat the second grade: - The father wears out 2 belts per year. - The son's education lasts for 11 years. - Therefore, the number of belts worn out by the father for the years when the son did not repeat the second grade is: 2 belts/year * 11 years = 22 belts.

2. Calculate the number of belts worn out by the father for the years when the son repeated the second grade: - The son repeated the second grade twice. - Each time the son repeated the second grade, it would add an additional year to the father's belt-wearing period. - Therefore, the number of belts worn out by the father for the years when the son repeated the second grade is: 2 belts/year * 2 years = 4 belts.

3. Calculate the total number of belts worn out by the father: - Add the number of belts worn out by the father for the years when the son did not repeat the second grade to the number of belts worn out by the father for the years when the son repeated the second grade. - Total number of belts worn out by the father = 22 belts + 4 belts = 26 belts.

Therefore, the father wore out a total of 26 belts over the course of his son's eleven years of education.