Question

Жесткий диск компьютера разбит на два логических диска :C и D.Если с диска D перенести 24 Мбайт информации на диск C,то объем информации на обоих дисках станет одинаковым .Если же с диска C перенести 27 Мбайт информации на диск D,то на диске D информации окажется в два раза больше ,чем на диске C.Определите объем информации на каждом диске .

Answer 1

Пусть на диске С  Х Мбайт информации, а на диске D  Y Мбайт. Получаем систему уравнений

Х + 24 = Y - 24

Y + 27 = 2 * (X - 27)

 

Y = X + 48

Y = 2 * X - 81

 

2 * X - 81 = X + 48

X = 129

 

Итак, на диске C  129 Байт информации, а на диске D -  177 Мбайт

 

 

Answer 2

Problem Analysis

We have a computer hard disk that is divided into two logical disks, C and D. If we transfer 24 MB of information from disk D to disk C, the amount of information on both disks will be the same. However, if we transfer 27 MB of information from disk C to disk D, the amount of information on disk D will be twice as much as on disk C. We need to determine the volume of information on each disk.

Solution

Let's assume the initial volume of information on disk C is x MB and the initial volume of information on disk D is y MB.

1. If we transfer 24 MB of information from disk D to disk C, the volume of information on both disks will be the same. This means that the volume of information on disk C will be x + 24 MB, and the volume of information on disk D will be y - 24 MB.

2. If we then transfer 27 MB of information from disk C to disk D, the volume of information on disk D will be twice as much as on disk C. This can be expressed as the equation 2(x + 24) = y - 24 + 27.

Let's solve this equation to find the values of x and y.

Calculation

Expanding the equation, we get 2x + 48 = y - 24 + 27.

Rearranging the terms, we have 2x - y = -3.

Now, let's substitute the value of y from the first equation into the second equation: 2x - (x + 24) = -3.

Simplifying the equation, we get x - 24 = -3.

Adding 24 to both sides, we have x = 21.

Substituting the value of x into the first equation, we get 21 + 24 = y.

Simplifying, we find that y = 45.

Answer

Therefore, the volume of information on disk C is 21 MB and the volume of information on disk D is 45 MB.