Question

1)x(27-0,3x)=0. 2)(6x-2,4)(3y+12)=0. 3)x(7x-4,2)(11x+3,3)=0. 4)x(1/3x+21)(2/3x-2,4)*(50-1/5x)=0 . Решите пожалуйста уравнения. Очень срочно.

Answer 1

Ответ:

Пошаговое объяснение:

1)x(27-0,3x)=0.

х1=0

27-0.3х=0

-0.3х=-27

х=-27:(-0.3)

х2=90

2)(6x-2,4)(3y+12)=0.

6х-2.4=0

6х=2.4

х=2.4:6

х1=0.4

3у+12=0

3у=-12

у=-12:3

у2=-4

3)x(7x-4,2)(11x+3,3)=0.

х1=0

7х-4.2=0

7х=4.2

х=4.2:7

х2=0.6

11х+3.3=0

11х=-3.3

х=-3.3:11

х3=-0.3

4)x(1/3x+21)(2/3x-2,4)*(50-1/5x)=0

х1=0

1/3x+21=0

1/3x=-21

x=-21:1/3=-21*3

x2=-63

2/3x-2.4=0

2/3x=2.4

x=2.4:2/3

x=12/5*3/2

x3=18/5=5 3/5

50-1/5x=0

1/5x=50

x=50:1/5=50*5

x4=250

Answer 2

Equation 1: x(27-0.3x) = 0

To solve this equation, we can set each factor equal to zero and solve for x.

Setting x = 0: x = 0

Setting 27 - 0.3x = 0: 27 - 0.3x = 0 -0.3x = -27 x = -27 / -0.3 x = 90

Therefore, the solutions to the equation x(27-0.3x) = 0 are x = 0 and x = 90.

Equation 2: (6x-2.4)(3y+12) = 0

To solve this equation, we can set each factor equal to zero and solve for x and y.

Setting 6x - 2.4 = 0: 6x = 2.4 x = 2.4 / 6 x = 0.4

Setting 3y + 12 = 0: 3y = -12 y = -12 / 3 y = -4

Therefore, the solution to the equation (6x-2.4)(3y+12) = 0 is x = 0.4 and y = -4.

Equation 3: x(7x-4.2)(11x+3.3) = 0

To solve this equation, we can set each factor equal to zero and solve for x.

Setting x = 0: x = 0

Setting 7x - 4.2 = 0: 7x = 4.2 x = 4.2 / 7 x = 0.6

Setting 11x + 3.3 = 0: 11x = -3.3 x = -3.3 / 11 x = -0.3

Therefore, the solutions to the equation x(7x-4.2)(11x+3.3) = 0 are x = 0, x = 0.6, and x = -0.3.

Equation 4: x(1/3x+21)(2/3x-2.4)(50-1/5x) = 0

To solve this equation, we can set each factor equal to zero and solve for x.

Setting x = 0: x = 0

Setting 1/3x + 21 = 0: 1/3x = -21 x = -21 * 3 x = -63

Setting 2/3x - 2.4 = 0: 2/3x = 2.4 x = 2.4 * 3/2 x = 3.6

Setting 50 - 1/5x = 0: 1/5x = 50 x = 50 * 5 x = 250

Therefore, the solutions to the equation x(1/3x+21)(2/3x-2.4)(50-1/5x) = 0 are x = 0, x = -63, x = 3.6, and x = 250.

Please note that these solutions are based on the given equations and calculations.