Question

Два велосипедиста выехали одновременно навстречу друг другу из пункта А и Б ,расстояние между которыми равно 30 км,и встретились через 1ч.Найдите скорость каждого велосипедиста ,если скорость одного из них на 2км/ч больше скорости другого.

Answer 1

30:1=30км/ч скорость одного велосипедиста
30+2=33км/ч скорость 2 велосипедиста

Answer 2

Problem Analysis

We are given that two cyclists start simultaneously from points A and B, which are 30 km apart, and meet after 1 hour. We need to find the speed of each cyclist, given that one cyclist's speed is 2 km/h greater than the other.

Solution

Let's assume the speed of one cyclist is x km/h. Then the speed of the other cyclist will be (x + 2) km/h.

We can use the formula speed = distance / time to find the speeds of the cyclists.

The distance traveled by the first cyclist in 1 hour is x km. Similarly, the distance traveled by the second cyclist in 1 hour is (x + 2) km.

Since the total distance between the two cyclists is 30 km, we can write the equation:

x + (x + 2) = 30

Simplifying the equation:

2x + 2 = 30

2x = 28

x = 14

Therefore, the speed of the first cyclist is 14 km/h and the speed of the second cyclist is 16 km/h.

Answer

The speed of the first cyclist is 14 km/h and the speed of the second cyclist is 16 km/h.