Question

1) (43+12)*3= 2)4*(64-31)= 3) 2*(20+31+16)= раскрыть скобки помогите пожалуйста

Answer 1

1)(пример) 165 (2) 132 (3) 134

Answer 2

1) (43+12)*3=43*3+12*3=129+36=165
2) 4*(64-31)=4*64-4*31=256-124=132
3) 2*(20+31+16)=2*20+2*31+2*16=40+62+32=134

Answer 3

1) (43 + 12) * 3

To solve this expression, we need to follow the order of operations, which is parentheses, multiplication, and addition.

First, we calculate the sum inside the parentheses: 43 + 12 = 55.

Then, we multiply the result by 3: 55 * 3 = 165.

Therefore, the answer to (43 + 12) * 3 is 165.

2) 4 * (64 - 31)

Again, we follow the order of operations.

First, we subtract 31 from 64: 64 - 31 = 33.

Then, we multiply the result by 4: 33 * 4 = 132.

Therefore, the answer to 4 * (64 - 31) is 132.

3) 2 * (20 + 31 + 16)

Once again, we follow the order of operations.

First, we add the numbers inside the parentheses: 20 + 31 + 16 = 67.

Then, we multiply the result by 2: 67 * 2 = 134.

Therefore, the answer to 2 * (20 + 31 + 16) is 134.

I hope this helps! Let me know if you have any other questions.