
Первые 2 ч турист шёл со скоростью 5 км\ч,затем ещё 3 ч со скорость 6 км\ч. Потом он обнаружил,что
потерял шапку,и побежал назад со скоростью 11 км\ч. Шапку турист нашёл,пробежав целый час.На каком расстоянии от начальной точки турист потерял шапку?Составь выражение для вычисления.

Ответы на вопрос




Problem Analysis
The problem states that a tourist walks at a speed of 5 km/h for the first 2 hours, then at a speed of 6 km/h for the next 3 hours. After realizing that they lost their hat, they run back at a speed of 11 km/h and find the hat after running for one hour. We need to determine the distance from the starting point where the tourist lost their hat.Solution
To solve this problem, we can break it down into two parts: the distance covered during the initial walk and the distance covered during the run back.1. Distance covered during the initial walk: - Speed during the initial walk = 5 km/h - Time during the initial walk = 2 hours - Distance covered during the initial walk = Speed * Time = 5 km/h * 2 hours = 10 km
2. Distance covered during the run back: - Speed during the run back = 11 km/h - Time during the run back = 1 hour - Distance covered during the run back = Speed * Time = 11 km/h * 1 hour = 11 km
3. Total distance from the starting point where the tourist lost their hat: - Total distance = Distance covered during the initial walk - Distance covered during the run back = 10 km - 11 km = -1 km
Since the total distance is negative, it means that the tourist lost their hat 1 km before reaching the starting point.
Expression for Calculation
The expression for calculating the distance from the starting point where the tourist lost their hat is:Distance = (Speed of initial walk * Time of initial walk) - (Speed of run back * Time of run back)
Substituting the given values:
Distance = (5 km/h * 2 hours) - (11 km/h * 1 hour)
Simplifying the expression:
Distance = 10 km - 11 km = -1 km
Therefore, the tourist lost their hat 1 km before reaching the starting point.
Please let me know if I can help you with anything else.


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