Question

Два автобуса одновременно отправляются с одной площади по маршрутам(разным). У одного рейс туда и обратно - 48 минут, у другого 1,12 минут. Через сколько времени автобусы опять встретятся на площади?

Answer 1

Если в условии задачи 1,12мин - это 1ч12мин,то

 

1ч12мин=72мин

48/72=2/3

48*3=72*2

144=144

144мин=2ч24мин

Ответ:автобусы встретятся через 2часа24мин

 

Answer 2

Problem Analysis

We have two buses that depart simultaneously from the same square but follow different routes. One bus completes a round trip in 48 minutes, while the other bus takes 1 hour and 12 minutes (72 minutes) for a round trip. We need to determine how long it will take for the buses to meet again at the square.

Solution

To find the time it takes for the buses to meet again at the square, we need to find the least common multiple (LCM) of the two round trip times.

The LCM is the smallest positive integer that is divisible by both numbers. We can calculate the LCM using various methods, such as prime factorization or the Euclidean algorithm. Let's use the prime factorization method.

Prime Factorization Method

To find the LCM using prime factorization, we need to factorize both round trip times into their prime factors and then multiply the highest power of each prime factor.

Let's factorize the round trip times:

- Round trip time of the first bus: 48 minutes = 2^4 * 3^1 - Round trip time of the second bus: 72 minutes = 2^3 * 3^2

Now, we can find the LCM by multiplying the highest power of each prime factor:

LCM = 2^4 * 3^2 = 144

Therefore, the buses will meet again at the square after 144 minutes.

Answer

The buses will meet again at the square after 144 minutes.