Question

Из одного города выехали легковая машина и маршрутка. Маршрутка двигалась со скоростью 40 км/ч, легковая машина двигалась быстрее и через 2 ч опередила маршрут-ка на 3о км. С какой скоростью двигалась легковая машина?

Answer 1

30 : 2 = 15 (км/ч) - скорость удаления.
40 + 15 = 55 (км/ч) - скорость легковой машины.
Ответ: 55 км/ч.

Answer 2

Problem Analysis

We are given that a car and a minibus (marshrutka) started from the same city. The minibus was traveling at a speed of 40 km/h, while the car was faster and overtook the minibus after 2 hours, covering a distance of 30 km more. We need to find the speed of the car.

Solution

Let's assume the speed of the car is x km/h.

After 2 hours, the minibus has traveled a distance of 40 km/h * 2 h = 80 km.

At this point, the car has covered a distance of 80 km + 30 km = 110 km.

Since the car overtakes the minibus, the time taken by the car to cover this distance is the same as the time taken by the minibus to cover 80 km.

We can set up the following equation to solve for the speed of the car:

110 km / x km/h = 80 km / 40 km/h

Simplifying the equation:

110 / x = 80 / 40

Cross-multiplying:

110 * 40 = 80 * x

Simplifying further:

4400 = 80x

Dividing both sides by 80:

x = 4400 / 80

Calculating the value:

x = 55

Therefore, the