Question

В Пакете лежали сливы.Сначала из него взяли 50% слив, а затем 50% остатка. После этого в пакете осталось 9 слив. Сколько слив было в пакете первоначально?

Answer 1

9 слив - 50% остатка

тогда весь остаток 2*9=18

18 слив - 50% начального числа

18*2=36 - начальное число слив

ответ 36 

Answer 2

Пусть х-первоначальное кол-во слив. Составим уравнение

х-0,5х-0,5(0,5х)=9

х-0,5х-0,25х=9

х-0,75х=9

0,25х=9

х=9/0,25

х=36

Ответ: 36 слив было в пакете первоначально

Answer 3

Problem Analysis

We are given a packet that initially contained plums. First, 50% of the plums were taken out, and then 50% of the remaining plums were taken out. After this, there were 9 plums left in the packet. We need to determine how many plums were initially in the packet.

Solution

Let's assume that the initial number of plums in the packet is x.

According to the problem, the following steps were taken: 1. 50% of the plums were taken out, leaving x/2 plums in the packet. 2. Then, 50% of the remaining plums were taken out, leaving (x/2) - (x/2)/2 plums in the packet.

We are given that there were 9 plums left in the packet after these steps. Therefore, we can set up the following equation:

(x/2) - (x/2)/2 = 9

To solve this equation, we can simplify it as follows:

(x/2) - (x/4) = 9

Multiplying both sides of the equation by 4 to eliminate the fractions, we get:

2x - x/2 = 36

Simplifying further, we have:

4x - x = 72

3x = 72

Dividing both sides of the equation by 3, we find:

x = 24

Therefore, there were initially 24 plums in the packet.

Answer

The packet initially contained 24 plums.