Question

Два самолета вылетели с аэродрома в одно и тоже время в противоположных направлениях через 10 минут после вылета расстояние между ними было 270 километров первый Самолет летел со средней скоростью 15 километров с какой средней скоростью КРАТКАЯ ЗАПИСЬ !!!!!

Answer 1

1) 10*15=150(км) пролетел первый сам.
2) 270-150=120(км) пролетел второй сам.
3) 120:10=12(км/мин) скорость второго сам.
Ответ: скорость второго самолета равна 12 км в минуту

Answer 2

15 километров чего???

Answer 3

Problem Statement

Two planes took off from an airport at the same time in opposite directions. After 10 minutes of takeoff, the distance between them was 270 kilometers. The first plane was flying at an average speed of 15 kilometers per hour. What was the average speed of the second plane?

Solution

To find the average speed of the second plane, we can use the formula:

Average Speed = Total Distance / Total Time

Let's calculate the total time taken by both planes to cover a distance of 270 kilometers.

The first plane flew for 10 minutes (or 10/60 hours) before the distance between the two planes was measured. Therefore, the total time taken by both planes is:

Total Time = Time taken by the first plane + Time taken by the second plane

Since the first plane flew for 10 minutes (or 10/60 hours), the second plane also flew for the same amount of time. So:

Total Time = (10/60) hours + (10/60) hours = (20/60) hours = 1/3 hours

Now, let's calculate the average speed of the second plane using the formula:

Average Speed = Total Distance / Total Time

Substituting the values:

Average Speed = 270 kilometers / (1/3) hours

Simplifying:

Average Speed = 270 kilometers * (3/1) hours

Average Speed = 810 kilometers per hour

Therefore, the average speed of the second plane is 810 kilometers per hour.