Question

Деталь в форме прямоугольного параллелепипеда с измерениями 7 см 10 см и 12 см изготовлена из алюминия. Найдите массу детали если кусок алюминия объемом 10см3 имеет массу 27 гр

Answer 1

7*10*12=840см3 84*27=2268грамм

Answer 2

Calculation of the Mass of the Aluminum Rectangular Parallelepiped

To find the mass of the aluminum rectangular parallelepiped, we can use the formula:

Mass (m) = Density (ρ) x Volume (V)

Given that the volume of the rectangular parallelepiped is 10 cm³ and the mass of a 10 cm³ piece of aluminum is 27 g, we need to find the density of aluminum to calculate the mass.

Finding the Density of Aluminum

To find the density of aluminum, we can rearrange the formula:

Density (ρ) = Mass (m) / Volume (V)

Using the given values, we have:

Density (ρ) = 27 g / 10 cm³

Now, we can calculate the density of aluminum.

Calculation of the Mass

Using the density of aluminum, we can calculate the mass of the rectangular parallelepiped:

Mass (m) = Density (ρ) x Volume (V)

Substituting the values:

Mass (m) = (27 g / 10 cm³) x (7 cm x 10 cm x 12 cm)

Simplifying the calculation:

Mass (m) = 27 g / 10 cm³ x 840 cm³

Mass (m) = 22680 g

Therefore, the mass of the aluminum rectangular parallelepiped is 22680 grams.