Question

Улей дает 30 кг меда 2 пятых этого меда надо ставить на тему пчела Сколько килограммов меда можно взять в улье Реши задачу двумя способами

Answer 1

1 вариант
30÷5×2=12(кг)
2 вариант
5\5-2\5=3\5
30÷5=6
6×3=18
30-18=12кг

Answer 2

1) 30:5=6 одна пятая часть всего меда
2) 6*2=12 кг часть меда которую необходимо оставить пчелам
3) 30-12=18 кг меда можно взять в улье.

1) 30:5=6 кг меда в одной части
2) 5-2=3 части меда можно взять
3) 6*3=18 кг меда можно взять в улье
ответ: 18 кг.

Answer 3

Problem Statement

Улей дает 30 кг меда. 2 пятых этого меда надо ставить на тему пчела. Сколько килограммов меда можно взять в улье? Решите задачу двумя способами.

Solution 1: Using Proportions

To solve this problem, we can set up a proportion to find the amount of honey that can be taken from the hive.

Let's denote the total amount of honey produced by the hive as H (30 kg in this case). According to the problem, 2/5 of this honey should be left for the bees.

Let's denote the amount of honey that can be taken from the hive as X. We can set up the following proportion:

(2/5)H = X

To find X, we can solve this proportion by cross-multiplying:

(2/5)H = X 2H = 5X X = (2/5)H

Substituting the value of H (30 kg) into the equation, we can find the amount of honey that can be taken from the hive:

X = (2/5) * 30 = 12 kg

Therefore, 12 kilograms of honey can be taken from the hive.

Solution 2: Using Fractions

Another way to solve this problem is by using fractions.

Let's denote the total amount of honey produced by the hive as H (30 kg in this case). According to the problem, 2/5 of this honey should be left for the bees.

To find the amount of honey that can be taken from the hive, we can subtract 2/5 of H from H:

X = H - (2/5)H

Simplifying the equation, we have:

X = (3/5)H

Substituting the value of H (30 kg) into the equation, we can find the amount of honey that can be taken from the hive:

X = (3/5) * 30 = 18 kg

Therefore, 18 kilograms of honey can be taken from the hive.

Summary

There are two ways to solve the problem: 1. Using proportions: By setting up a proportion, we find that