Question

Найти общее решение ду y^11+2y'+5y=0

Answer 1

Y''+2y'+5y=0:  k=y'
k^2+2K+5=0
D=2^2-4*1*5=4-20=-16<0
нет решение. Но если исползуваем комплектные числи ,то можем найти комплектную решению.
k1=(-2+корень(-16))/2=[-1=i^2]=(-2+корен(16*i^2))/2=(-2+4*i)/2=-1+2i
k2=(-2-корень(-16))/2=[-1=i^2]=(-2-корен(16*i^2))/2=(-2-4*i)/2=-1-2i
y=C1*e^((-1+2i)*x)+C2*e^((-1-2i)*x).

Answer 2

Solution for the Differential Equation y^11 + 2y' + 5y = 0

To find the general solution for the differential equation y^11 + 2y' + 5y = 0, we can use various methods such as substitution, separation of variables, or integrating factors. However, for this particular equation, it may not be possible to find an explicit solution using elementary functions.

Unfortunately, the search results provided by You.com do not contain any relevant information or formulas specifically addressing the solution to the given differential equation. Therefore, it is not possible to provide a detailed solution or a general formula for this equation based on the available information.

It is worth noting that differential equations can have different types of solutions, including explicit formulas, implicit formulas, or numerical approximations. In some cases, it may also be necessary to use numerical methods or computer simulations to approximate the solution.

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