Question

X/10-y/5=0 и 5x/3+y/6=7 пожалуйста решите систему способом подстановки

Answer 1

(х-2у)/10=0     /*10
(10х+у)/6=7    /*6

х-2у=0
10х+у=42

х=2у
10*2у + у=42

21у=42
у=2

х=2*2=4

Ответ: (4;2)

Answer 2

Problem Statement

We are given the following system of equations: ``` X/10 - y/5 = 0 5x/3 + y/6 = 7 ``` We need to solve this system using the substitution method.

Solution

To solve the system of equations using the substitution method, we'll solve one equation for one variable and substitute it into the other equation.

Let's solve the first equation for x: ``` X/10 - y/5 = 0 ``` Multiplying both sides of the equation by 10, we get: ``` X - 2y = 0 ``` Now, we can express x in terms of y: ``` X = 2y ```

Substituting this value of x into the second equation, we get: ``` 5x/3 + y/6 = 7 ``` Substituting x = 2y, we have: ``` 5(2y)/3 + y/6 = 7 10y/3 + y/6 = 7 ``` Multiplying both sides of the equation by 6 to eliminate the denominators, we get: ``` 20y + y = 42 21y = 42 y = 2 ```

Now, substituting the value of y back into the equation X = 2y, we get: ``` X = 2(2) X = 4 ```

Therefore, the solution to the system of equations is X = 4 and y = 2.

Answer: The solution to the system of equations X/10 - y/5 = 0 and 5x/3 + y/6 = 7, using the substitution method, is X = 4 and y = 2.