Вопрос задан 08.05.2019 в 13:43. Предмет Математика. Спрашивает Хусаинова Айсылу.

Лодка за 2 часа по течению и за 4 часа против течения прошла 24 км .найдите скорость лодки в

стоячей воде, если скорость реки 3 км/час.помогите пожайлуста!!!!
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Отвечает Кот Ренат.
Х - скорость лодки
(х + 3)*2 + (х - 3)*4  = 24
2х + 6 + 4х - 12 = 24
6х = 30
х = 5
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Problem Analysis

We are given that a boat travels a distance of 24 km in 2 hours downstream (with the current) and in 4 hours upstream (against the current). The speed of the river current is given as 3 km/h. We need to find the speed of the boat in still water.

Let's assume the speed of the boat in still water is x km/h.

Downstream Speed

When the boat is traveling downstream, it gets a boost from the current. So the effective speed of the boat is the sum of its speed in still water and the speed of the current.

The time taken to travel downstream is given as 2 hours, and the distance traveled is 24 km. We can use the formula:

Distance = Speed × Time

Substituting the values, we get:

24 = (x + 3) × 2

Simplifying the equation, we have:

2x + 6 = 24

2x = 18

x = 9

So, the speed of the boat in still water is 9 km/h.

Upstream Speed

When the boat is traveling upstream, it has to overcome the resistance of the current. So the effective speed of the boat is the difference between its speed in still water and the speed of the current.

The time taken to travel upstream is given as 4 hours, and the distance traveled is 24 km. We can use the formula:

Distance = Speed × Time

Substituting the values, we get:

24 = (x - 3) × 4

Simplifying the equation, we have:

4x - 12 = 24

4x = 36

x = 9

Again, we find that the speed of the boat in still water is 9 km/h.

Conclusion

The speed of the boat in still water is 9 km/h.

Please note that the search results provided did not directly answer the question. The solution was derived using basic mathematical principles and formulas.

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