Question

Пирпериметр прямоугольника 66 дм. Длина одной его стороны составляет 3/11 периметра. Найдите площадь прямоугольника

Answer 1

66*3/11=18 дм - длина стороны
66:2-18=15 дм -  ширина
18*15=270 дм² - площадь

Answer 2

Calculation of the Rectangle's Perimeter

To find the area of a rectangle, we first need to calculate its perimeter. The problem states that the perimeter of the rectangle is 66 dm, and the length of one of its sides is 3/11 of the perimeter.

Let's assume the length of the rectangle is L and the width is W. The perimeter of a rectangle is given by the formula:

Perimeter = 2(L + W)

According to the problem, one side of the rectangle is 3/11 of the perimeter. So we can write:

L = (3/11) * Perimeter

Substituting the given perimeter value of 66 dm, we can calculate the length of the rectangle:

L = (3/11) * 66 = 18 dm

Calculation of the Rectangle's Width

To find the width of the rectangle, we can use the formula for the perimeter:

Perimeter = 2(L + W)

Substituting the known values of the perimeter and length, we can solve for the width:

66 = 2(18 + W)

Simplifying the equation:

66 = 36 + 2W

2W = 66 - 36

2W = 30

W = 30/2

W = 15 dm

Calculation of the Rectangle's Area

Now that we have the length and width of the rectangle, we can calculate its area using the formula:

Area = Length * Width

Substituting the values we found:

Area = 18 dm * 15 dm = 270 dm^2

Therefore, the area of the rectangle is 270 square decimeters.

Please note that the sources provided did not contain specific information related to this problem. The solution was derived using mathematical principles and formulas.