Вопрос задан 06.05.2019 в 21:43. Предмет Математика. Спрашивает Limova Daria.

Вероятность появления бракованной детали при поступлении изделий из первого завода составляет

0,005, а при поступлении изделий со второго завода - 0,008. Найдите вероятность появления бракованной детали в партии, содержащей 1200 деталей с первого и 1800 деталей со второго завода.
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Отвечает Маирова Ариана.
(0,005*1200+0,008*1800)/(1200+1800)=(6+14,4)/3000=0,0068
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Probability of Defective Parts

To find the probability of a defective part in a batch containing 1200 parts from the first factory and 1800 parts from the second factory, we need to calculate the probability separately for each factory and then combine the results.

The probability of a defective part from the first factory is given as 0.005, and the probability of a defective part from the second factory is given as 0.008.

Let's calculate the probability of a defective part from the first factory:

Probability of a defective part from the first factory = 0.005

Now, let's calculate the probability of a defective part from the second factory:

Probability of a defective part from the second factory = 0.008

To find the probability of a defective part in the batch containing 1200 parts from the first factory and 1800 parts from the second factory, we can use the weighted average of the probabilities:

Probability of a defective part in the batch = (Probability of a defective part from the first factory * Number of parts from the first factory + Probability of a defective part from the second factory * Number of parts from the second factory) / Total number of parts in the batch

Substituting the given values:

Probability of a defective part in the batch = (0.005 * 1200 + 0.008 * 1800) / (1200 + 1800)

Simplifying the expression:

Probability of a defective part in the batch = (6 + 14.4) / 3000

Probability of a defective part in the batch = 20.4 / 3000

Probability of a defective part in the batch ≈ 0.0068

Therefore, the probability of a defective part in the batch containing 1200 parts from the first factory and 1800 parts from the second factory is approximately 0.0068.

Please note that the search results provided by You.com did not contain specific information related to the calculation of the probability of defective parts in a batch. The calculation was done based on the given probabilities and the assumption that the defective parts are independent of each other.

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