Question

Воробей догоняет стрекозу,находящуюся от него на расстоянии 7,4 м.скорость стрекозы 3,7м/с,а скорость воробья 5,8м/с. Чему будет равно расстояние между воробьем и стрекозой через 1с?

Answer 1

5,8-3,7=2,1 м/сек скорость удаления
Ответ:2,1 метр

Answer 2

Calculation of the Distance between the Sparrow and the Dragonfly

To calculate the distance between the sparrow and the dragonfly after 1 second, we can use the formula:

Distance = Initial Distance + (Relative Velocity × Time)

Given: - Initial distance between the sparrow and the dragonfly = 7.4 m - Velocity of the dragonfly = 3.7 m/s - Velocity of the sparrow = 5.8 m/s - Time = 1 second

Using the formula, we can calculate the distance between the sparrow and the dragonfly after 1 second:

Distance = 7.4 m + ((5.8 m/s - 3.7 m/s) × 1 s)

Simplifying the equation:

Distance = 7.4 m + (2.1 m/s × 1 s)

Distance = 7.4 m + 2.1 m

Distance = 9.5 m

Therefore, the distance between the sparrow and the dragonfly after 1 second will be 9.5 meters.