Question

В трех автобусах ехало на экскурсию 68 ребят,во втором автобусе детей было на 6 больше, чем, в первом, и на 8 меньше чем в третьем, сколько детей ехало в каждом автобусе.

Answer 1

В трех автобусах - 68 чел
в 1 - на 6 больше чем во втором и на 8 меньше чем в третьем 
во 2 - ?
в 3 - ?
1) 6 + 8 = на 14 (чел) во втором автобусе меньше чем в третьем
2) 68 - 8 - 14 = 46 (чел) 3 части
3) 46 : 3 = 16 (чел) второй автобус
4) 16 + 6 = 22 (чел) в первом
5) 16 + 14 = 30 (чел) в третьем
Ответ: 16 во 2, 22 в 1, 30 в 3

Answer 2

х - ехало в первом
тогда х+6  - ехало во втором
и х+6+8 = х+14  - в третьем
х + (х+6) + (х+14) = 68
3х + 20 = 68
3х = 48
х = 16
х+6 = 22
х + 14 = 30
Ответ: 16, 22, 30.

Answer 3

Problem Analysis

We are given information about three buses that were going on an excursion. The total number of children in the three buses is 68. The second bus had 6 more children than the first bus, and 8 fewer children than the third bus. We need to determine how many children were in each bus.

Solution

Let's assume the number of children in the first bus is x.

According to the given information, the second bus had 6 more children than the first bus, so the number of children in the second bus is x + 6.

The third bus had 8 fewer children than the third bus, so the number of children in the third bus is x + 6 + 8 or x + 14.

The total number of children in the three buses is 68, so we can write the equation:

x + (x + 6) + (x + 14) = 68

Simplifying the equation:

3x + 20 = 68

Subtracting 20 from both sides:

3x = 48

Dividing both sides by 3:

x = 16

Therefore, there were 16 children in the first bus, 16 + 6 = 22 children in the second bus, and 16 + 14 = 30 children in the third bus.

Answer

There were 16 children in the first bus, 22 children in the second bus, and 30 children in the third bus.