Question

Помогитееее пожалуйстаааа срочноо надооо ((((( Гасан начал движение на автомобиле со скоростью 60 км/ч в сторону железнодорожного вокзала в восточном направлении в 14.00. Через час , в направлении на север, со скоростью 50км/ч из той же точки начал движение Башир .Какое растояние будет между ними в 16.00 ?

Answer 1

Гасан до 13 часов проехал 60км/ч×1ч=60км+1ч до 14 часов ещё 60км.
Гасан-2ч.×60км/ч=1 20km.
Башир проехал 1 ч.
Будет-1ч×50км/ч=50км.

Answer 2

1)16-14=2часа
2)60*2=120км
3)16-15=1час
4)50*1=50км
5)120+50=170км
Ответ:170км

Answer 3

To find the distance between Gasan and Bashir at 16:00, we need to calculate the distances each of them traveled during the given time period.

Distance traveled by Gasan:

Gasan started moving at 14:00 with a speed of 60 km/h in the eastern direction. By 16:00, he would have been traveling for 2 hours. Therefore, the distance traveled by Gasan can be calculated as follows:

Distance traveled by Gasan = Speed × Time = 60 km/h × 2 hours = 120 km [[1]].

Distance traveled by Bashir:

Bashir started moving in the northern direction from the same point at 15:00 with a speed of 50 km/h. By 16:00, he would have been traveling for 1 hour. Therefore, the distance traveled by Bashir can be calculated as follows:

Distance traveled by Bashir = Speed × Time = 50 km/h × 1 hour = 50 km [[2]].

Distance between Gasan and Bashir at 16:00:

To find the distance between Gasan and Bashir at 16:00, we need to calculate the distance between their final positions. Since Gasan was moving in the eastern direction and Bashir was moving in the northern direction, we can treat their movements as forming a right-angled triangle.

Using the Pythagorean theorem, we can calculate the distance between them:

Distance = √(Distance_Gasan^2 + Distance_Bashir^2) = √(120 km^2 + 50 km^2) ≈ √(14400 km^2 + 2500 km^2) ≈ √16900 km^2 ≈ 130 km [[3]].

Therefore, the distance between Gasan and Bashir at 16:00 is approximately 130 kilometers.

I hope this helps! Let me know if you have any further questions.