Question

Незнайка съел в 7 раз меньше вареников , чем Пончик. Сколько каждый из них если Пончик съел на 48 вареников больше, чем Незнайко?

Answer 1

пусть х вареников съел незнака

у - съел пончик

7х=у

х+48=у

 

х+48=7х

6х=48

х=8 - съел незнайка

8*7=56 - съел пончик

Answer 2

пусть Пончик съел 7х вареников,тогда Незнайка х вареников,с другой стороны

х+48=7х

6х=48

х=8

7х=56

Ответ:8,56

Answer 3

Calculating the Amount Eaten by Each

To solve this problem, we can use algebra to represent the given information and then solve for the unknown quantities.

Let's denote: - The amount eaten by Neznayka as N. - The amount eaten by Ponchik as P.

We are given that Neznayka ate 7 times less than Ponchik, so we can express this as: N = P/7.

We are also given that Ponchik ate 48 more vareniks than Neznayka, so we can express this as: P = N + 48.

Solving for the Amount Eaten by Each

Substituting the first equation into the second equation, we get: P = (P/7) + 48.

Multiplying through by 7 to clear the fraction, we get: 7P = P + 336.

Subtracting P from both sides, we get: 6P = 336.

Dividing both sides by 6, we find: P = 56.

Substituting the value of P back into the equation P = N + 48, we find: 56 = N + 48.

Subtracting 48 from both sides, we get: N = 8.

Conclusion

Therefore, Neznayka ate 8 vareniks, and Ponchik ate 56 vareniks.