Question

В купейных вагонах первого поезда-180мест,второго поезда-252места , третьего поезда- 216 мест какое может быть наибольшееколичество мест в одном купейном вагоне , если в каждом купейном вагоне одинаковое число мест

Answer 1

Гдето может 180!!!!!!

Answer 2

Calculating the Maximum Number of Seats in a Compartment Carriage

To find the maximum number of seats in a compartment carriage, we can use the concept of finding the greatest common divisor (GCD) of the seat capacities of the three trains.

Given: - First train: 180 seats - Second train: 252 seats - Third train: 216 seats

We need to find the largest number that divides each of these numbers without leaving a remainder.

Finding the Greatest Common Divisor (GCD)

The GCD of the seat capacities can be calculated using various methods, such as prime factorization, Euclidean algorithm, or using a calculator with a GCD function.

Let's use the prime factorization method to find the GCD.

The prime factorization of the seat capacities is as follows: - 180 = 2^2 * 3^2 * 5 - 252 = 2^2 * 3^2 * 7 - 216 = 2^3 * 3^3

Calculating the GCD

The GCD is the product of the common prime factors raised to the lowest powers they appear with.

The common prime factors are 2 and 3. The lowest powers they appear with are 2^2 and 3^2.

So, the GCD of 180, 252, and 216 is 2^2 * 3^2, which equals 36.

Conclusion

The maximum number of seats in a compartment carriage, given the seat capacities of the three trains, is 36.