Question

Помогите решить задачу :без иксов в три пакета надо разложить 140 орехов так, чтобы их количество в первом пакете было в два раза меньше,чем во втором, но в два раза больше,чем в третьем.Сколько орехов будет в каждом пакете?

Answer 1

4+2+1=7 части
140:7=20 в 3 пакете
20*2=40 в 1 пакете
40*2 = 80 в 2 пакете

Answer 2

Problem Analysis

To solve this problem, we need to distribute 140 nuts into three packets in such a way that the number of nuts in the first packet is half the number in the second packet and twice the number in the third packet.

Solution

Let's denote the number of nuts in the first, second, and third packets as A, B, and C, respectively. We can set up the following equations based on the given conditions: 1. A + B + C = 140 (total number of nuts) 2. A = (1/2)B (number of nuts in the first packet is half the number in the second packet) 3. A = 2C (number of nuts in the first packet is twice the number in the third packet)

Calculations

We can solve these equations to find the values of A, B, and C.

From equation 2, we can express B in terms of A: B = 2A

Substitute B = 2A into equation 1: A + 2A + C = 140 3A + C = 140

From equation 3, we can express C in terms of A: C = A/2

Substitute C = A/2 into the modified equation 1: 3A + A/2 = 140 6A + A = 280 7A = 280 A = 40

Now that we have the value of A, we can find B and C: B = 2A = 2*40 = 80 C = A/2 = 40/2 = 20

Answer

So, there will be 40 nuts in the first packet, 80 nuts in the second packet, and 20 nuts in the third packet.