Question

Условия к задаче.рыбак поймал 28 рыб. несколько меньших рыб он отпустил. осталась 21рыба.во сколько раз больше рыб осталось у рыбака чем он отпустил

Answer 1

28-21=7 (р)-маленьких. 28*7=196(р) больше

Answer 2

Task Conditions

A fisherman caught 28 fish. He released some of the smaller fish and was left with 21 fish. The question is: by how many times are the remaining fish more than the ones he released?

Solution

To solve this problem, we can use the following formula: Difference in the number of remaining and released fish / Number of released fish

Calculation

Using the given information: Difference in the number of remaining and released fish = 28 - 21 = 7 Number of released fish = 28 - 21 = 7

Now, we can calculate the result: 7 / 7 = 1

So, the remaining fish are 1 time more than the ones the fisherman released.

I hope this helps! If you have any further questions, feel free to ask.