Question

Решите систему уравнений {х^2+3у^2=31 {2х^2+6у2=31х решите пожалуста

Answer 1

Х²+3у²=31
2х²+6у²=31х
3y²=31-x²
2x²+2(31-x²)=31x
2x²+62-2x²-31x=0
-31x=-62
x=62:31
x=2

2²+3y²=31
4+3y²=31
3y²=27
y²=9
y=3, y=-3

Answer 2

Solving the System of Equations

To solve the system of equations {х^2+3у^2=31} and {2х^2+6у^2=31}, we can use the method of substitution or elimination to find the values of x and y that satisfy both equations.

First, let's solve the first equation for x^2: x^2 = 31 - 3y^2.

Now, we can substitute this expression for x^2 into the second equation: 2(31 - 3y^2) + 6y^2 = 31.

Solving this equation will give us the value of y. After finding y, we can substitute it back into the equation x^2 = 31 - 3y^2 to find the corresponding value of x.

Let's calculate the values of x and y using the provided equations.