Question

К мельнице привезли 58 мешки пшеницы и 38 мешки ржи.Пшеницы привезли на 16 центнеров больше чем ржи.Сколько отдельно килограммов ржи и пшеницы завезено, если все мешки с зерном имели одинаковую массу?

Answer 1

1)58-38=20(м.)-разница между кол-вом мешков пшеницы и ржи

2)16:20=0,8(ц)-в 1 мешке

0,8ц=80кг

3)38*80=3040(кг)-ржи

4)58*80=4640(кг)-пшеницы

Ответ:3040кг,4640кг

Answer 2

Ржи привезли 1,25•38=47,5 центнеров

Пшеницы 1,25•58=72,5 центнеров

Answer 3

Problem Analysis

We are given that 58 bags of wheat and 38 bags of rye were brought to the mill. The wheat was brought in 16 centners (1 centner = 100 kilograms) more than the rye. We need to find the separate weights of wheat and rye if all the bags had the same weight.

Solution

Let's assume that each bag of wheat and rye has a weight of x centners.

According to the given information, the total weight of wheat is 16 centners more than the total weight of rye. Therefore, we can write the equation:

58x = 38x + 16

Simplifying the equation, we get:

20x = 16

Dividing both sides of the equation by 20, we find:

x = 0.8

So, each bag of wheat and rye weighs 0.8 centners.

To find the separate weights of wheat and rye, we can multiply the weight of each bag by the number of bags:

- Weight of wheat = 58 bags * 0.8 centners/bag - Weight of rye = 38 bags * 0.8 centners/bag

Calculating these values, we get:

- Weight of wheat = 46.4 centners - Weight of rye = 30.4 centners

Therefore, the separate weights of wheat and rye brought to the mill are 46.4 centners and 30.4 centners, respectively.

Answer

The separate weights of wheat and rye brought to the mill are 46.4 centners and 30.4 centners, respectively.