
-y+1 целая 2\3 =-2 целых 1\6


Ответы на вопрос




I can help you with this math problem. You want to find the value of y in the equation:
$$y + 1 \frac{2}{3} = -2 \frac{1}{6}$$
To do this, you need to subtract $1 \frac{2}{3}$ from both sides of the equation. This will isolate y on the left side and give you a new equation:
$$y = -2 \frac{1}{6} - 1 \frac{2}{3}$$
Now, you need to subtract the fractions on the right side. To do this, you need to find a common denominator for the fractions. The lowest common denominator for $6$ and $3$ is $6$. So, you need to multiply the numerator and denominator of the second fraction by $2$ to get an equivalent fraction with a denominator of $6$. This will give you:
$$y = -2 \frac{1}{6} - 1 \frac{4}{6}$$
Now, you can subtract the fractions by subtracting the numerators and keeping the same denominator. This will give you:
$$y = -2 \frac{1 - 4}{6}$$
Simplify the fraction by subtracting the numerators:
$$y = -2 \frac{-3}{6}$$
Reduce the fraction by dividing the numerator and denominator by the greatest common factor, which is $3$:
$$y = -2 \frac{-1}{2}$$
Now, you have the final answer for y. You can write it as a mixed number or as a decimal. As a mixed number, it is:
$$y = -2 \frac{1}{2}$$
As a decimal, it is:
$$y = -2.5$$
I hope this helps you understand how to solve this equation.


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