Question

Сплав состоит из19 частей алюминия и 2 частей магния ( по массе ) какова масса сплава если в нём магния на 34 кг меньше чем алюминия?

Answer 1

Х - одна часть
19х-2х=34
17х=34
х=2 (кг)
19*2=38 (кг) - аллюминия
2*2=4 (кг) - магния
38+4 = 42 (кг) всего

Answer 2

Calculating the Mass of the Alloy

To calculate the mass of the alloy, we can use the given information that the alloy consists of 19 parts of aluminum and 2 parts of magnesium by mass, and that there is 34 kg less magnesium than aluminum.

The mass of the alloy can be calculated using the following steps:

1. Let's assume the mass of each part of aluminum is represented by x kg, and the mass of each part of magnesium is represented by y kg. 2. Since the alloy consists of 19 parts of aluminum and 2 parts of magnesium, the total mass of aluminum in the alloy is 19x kg, and the total mass of magnesium in the alloy is 2y kg. 3. Given that there is 34 kg less magnesium than aluminum, we can express this as an equation: 19x - 2y = 34.

Solution

To solve for the mass of the alloy, we can use the equation 19x - 2y = 34 and solve for x and y.

Let's proceed with the calculation:

From Source we have the equation: 19x - 2y = 34.

Now, we can solve for the mass of the alloy using this equation.