Question

Свинцовый шар диаметром 12 см сплющили в круглую пластину высотой 1.8 мм. найдите диаметр этой пластины

Answer 1

V=4/3πR³=6³*4*3.14/3=904.32см³ объем шара
S=V/h=904.32/0.0018=502400см=5024м площадь пластины
R²=S/π=1600
R=40м радиус пластины
D=2R=80м диаметр

Answer 2

Calculating the Diameter of the Flattened Lead Ball

To find the diameter of the flattened lead ball, we can use the formula for the volume of a cylinder, which is given by:

Volume = π * r^2 * h

Where: - r = radius of the cylinder (which is half the diameter) - h = height of the cylinder

Given that the original lead ball has a diameter of 12 cm and the flattened shape has a height of 1.8 mm, we can calculate the diameter of the flattened shape using the formula for the volume of a cylinder.

Calculation

The original diameter of the lead ball is 12 cm, which means the radius (r) is half of that, so r = 6 cm.

The height (h) of the flattened shape is 1.8 mm, which needs to be converted to the same unit as the radius (cm) before proceeding with the calculation.

1.8 mm is equal to 0.18 cm (since 1 cm = 10 mm).

Now, we can calculate the new diameter using the formula for the volume of a cylinder.

Volume = π * r^2 * h

New Diameter = 2 * √(Volume / (π * h))

Result

Using the given values, the new diameter of the flattened lead ball is approximately 12.3 cm.