
Мотогонщик преодолел первый участок трассы за 54 с,второй за 46 с,а третий на n быстрее,чем
второй.Сколько ремени затратил мотогонщик на прохождение этих 3-ёх участков?Найдите значение полученного выражения если n=9;17;22 Помогите решить плииииииизик!!!!!!!

Ответы на вопрос

2 участок 46с
3 учаток 46-n с
если n= 9с то общее время 54+46+46-9= 137с
n=17 n 54+46+46-17=129c
т= 22 54+46+46-22= 124с



2 участок-46 с
3 участок-46-n с
n=17 54+46+46-17=129 (c)
n=22 54+46+46-22=124 (c)



Problem Analysis
We are given that a motorcycle racer completed the first section of the track in 54 seconds, the second section in 46 seconds, and the third section faster than the second section by an unknown amount, denoted as 'n'. We need to find the total time taken by the racer to complete all three sections and calculate the value of the expression for different values of 'n' (9, 17, and 22).Solution
To find the total time taken by the racer to complete all three sections, we need to add the times taken for each section.Let's denote the time taken for the first section as 't1', the time taken for the second section as 't2', and the time taken for the third section as 't3'.
We are given that: - t1 = 54 seconds - t2 = 46 seconds - t3 = t2 - n (the third section is faster than the second section by 'n' seconds)
To find the total time, we add the times taken for each section: Total time = t1 + t2 + t3
Substituting the given values: Total time = 54 + 46 + (46 - n)
Simplifying the expression: Total time = 100 - n
Now, we can calculate the total time for different values of 'n': - For n = 9: Total time = 100 - 9 = 91 seconds - For n = 17: Total time = 100 - 17 = 83 seconds - For n = 22: Total time = 100 - 22 = 78 seconds
Therefore, the motorcycle racer took 91 seconds to complete all three sections when n = 9, 83 seconds when n = 17, and 78 seconds when n = 22.
Answer
The motorcycle racer took 91 seconds to complete all three sections when n = 9, 83 seconds when n = 17, and 78 seconds when n = 22.

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