Question

Решите!!! С аэродрома одновременно поднялись два самолёта и направились в противоположных направлениях. Через 3 часа расстояние между ними было 4410 км. Определи скорость первого самолёта, если скорость второго - 620 км/ч.

Answer 1

620*3=1860 км прошёл второй самолёт.
4410-1860=2550 км прошел первый самолёт.
2550:3=850 км в час была скорость первого самолёта.

Answer 2

1) 850*3=2550 - S одного самолета (пролетит один самолет )2) 2)2550+2550=5100 - S между ними (расстаяние между ними , за 3 часа. 

Answer 3

Problem Analysis

We are given that two airplanes took off from an airport simultaneously and flew in opposite directions. After 3 hours, the distance between them was 4410 km. We need to determine the speed of the first airplane, given that the speed of the second airplane is 620 km/h.

Solution

Let's assume the speed of the first airplane is x km/h.

The distance traveled by the first airplane in 3 hours is 3x km.

The distance traveled by the second airplane in 3 hours is 3 * 620 km.

The sum of the distances traveled by both airplanes is equal to the total distance between them, which is 4410 km.

Therefore, we can write the equation:

3x + 3 * 620 = 4410

Simplifying the equation:

3x + 1860 = 4410

Subtracting 1860 from both sides:

3x = 2550

Dividing both sides by 3:

x = 850

Therefore, the speed of the first airplane is 850 km/h.

Answer

The speed of the first airplane is 850 km/h.