Question

Решите пожалуста 0,3(3x-1)+0,2=5(0,1-0,2x)-0,1

Answer 1

0,3(3х-1)+0,2=5(0,1-0,2х)-0,1

0,9х-0,3+0,2=0,5-1х-0,1
0,9х-0,1=0,5-х-0,1
0,9х-0,1=0,4-х
09х+х=0,4+0,1
1,9х=0,5
х=0,5 : 1,9
5 19
х = _ ÷ _
10 10
5 10
х = _ × _
10 19

1
х = 5 × _
19

5
х = _
19

Answer 2

I can help you solve this equation. First, let's rewrite it in a more readable form:

$$0.3(3x-1)+0.2=5(0.1-0.2x)-0.1$$

Next, let's expand the brackets and simplify the terms:

$$0.9x-0.3+0.2=0.5-1x-0.1$$ $$1.9x=0.4$$

Finally, let's divide both sides by 1.9 to get the value of x:

$$x=\frac{0.4}{1.9}$$ $$x\approx 0.21$$

Therefore, the solution is x = 0.21 (rounded to two decimal places). I hope this helps.Ответь+подробно.+Решите+пожалуста+0,3(3x-1)+0,2=5(0,1-0,2x)-0,1