Question

Решить задачу арифметическим и алгебраическим способами За 6 одинаковых учебников заплатили на 42 рубля больше чем за 5 одинаковых тетрадей.Учебник на 3 рубля дороже тетради.Определите цену учебника и тетради

Answer 1

Ой да я не знаю
думай сама

Answer 2

Problem Analysis

To solve this problem, we need to determine the price of a textbook and a notebook. We are given the following information: - The cost of 6 identical textbooks is 42 rubles more than the cost of 5 identical notebooks. - The price of a textbook is 3 rubles more than the price of a notebook.

Let's denote the price of a textbook as x and the price of a notebook as y. We can set up the following equations based on the given information:

Equation 1: 6x = 5y + 42 Equation 2: x = y + 3

We can solve this system of equations to find the values of x and y.

Solution

To solve the system of equations, we can use the substitution method. We'll substitute the value of x from Equation 2 into Equation 1.

Substituting x = y + 3 into Equation 1, we get: 6(y + 3) = 5y + 42

Simplifying the equation: 6y + 18 = 5y + 42

Subtracting 5y from both sides: y + 18 = 42

Subtracting 18 from both sides: y = 24

Now that we have the value of y, we can substitute it back into Equation 2 to find the value of x: x = y + 3 x = 24 + 3 x = 27

Therefore, the price of a textbook is 27 rubles and the price of a notebook is 24 rubles.

Answer

The price of a textbook is 27 rubles and the price of a notebook is 24 rubles.