Question

Ученик может за 6ч.а мастер за2/3этого времени.Вначале ученик работал2ч.а затем оставшуюся часть работы они вместе сделали.Сколько времени они работали вместе?

Answer 1

1)6-2=4
2)4:3=1,3
3)1,3+2=3,3 часа вместе с мастером
Моё мнение

Answer 2

Problem Analysis

We are given that a student can complete a task in 6 hours and a master can complete 2/3 of the task in the same amount of time. The student initially worked for 2 hours, and then they completed the remaining work together. We need to find out how much time they worked together.

Solution

Let's break down the problem step by step:

1. The student can complete the task in 6 hours, so their work rate is 1/6 of the task per hour. 2. The master can complete 2/3 of the task in the same amount of time, so their work rate is (2/3) / 6 = 1/9 of the task per hour. 3. The student worked for 2 hours, so they completed 2 * (1/6) = 1/3 of the task. 4. The remaining work is 1 - 1/3 = 2/3 of the task. 5. Let's assume the time they worked together is x hours. During this time, the student and the master completed a combined work rate of (1/6 + 1/9) * x = 5/18 * x. 6. According to the problem, the combined work rate is equal to the remaining work, so we have the equation 5/18 * x = 2/3. 7. Solving for x, we find x = (2/3) / (5/18) = (2/3) * (18/5) = 12/5 = 2.4 hours.

Therefore, the student and the master worked together for 2.4 hours.

Answer

The student and the master worked together for 2.4 hours.