Question

ПЛИЗ ПОМОГИТЕ СРОЧНО. Согласно расписанию, автобус курсирует по маршруту из пункта A в пункт B и обратно с постоянной скоростью и без остановок. На пути из A в B он был вынужден на некоторое время остановиться, поэтому на обратном пути увеличил скорость на 25%. Приехав в A с 10 минутным отклонением от расписания, он уменьшил свою последнюю скорость на 24% и прибыл в B вовремя. Сколько минут длилась вынужденная остановка

Answer 1

Ответ 28 минут решение смотри в приложении

Answer 2

Calculation of the Duration of the Forced Stop

To calculate the duration of the forced stop, we need to analyze the given information step by step.

1. The bus travels from point A to point B and back at a constant speed without any stops. 2. On the way from A to B, the bus had to make a stop for some time. 3. As a result, on the return trip, the bus increased its speed by 25%. 4. When the bus arrived at point A, it was 10 minutes behind schedule. 5. To compensate for the delay, the bus reduced its speed by 24%. 6. The bus arrived at point B on time.

Let's break down the information and calculate the duration of the forced stop.

1. The bus was 10 minutes behind schedule when it arrived at point A. 2. To compensate for the delay, the bus reduced its speed by 24%. 3. The bus arrived at point B on time.

To find the duration of the forced stop, we need to calculate the time it took for the bus to travel from point A to point B at reduced speed and compare it to the time it would have taken at the original speed.

Let's assume the original speed of the bus is represented by x units of distance per unit of time.

1. At the original speed, the bus would have taken x units of time to travel from point A to point B. 2. However, due to the 24% reduction in speed, the bus took 1.24x units of time to travel from point A to point B.

Since the bus arrived at point B on time, the time it took to travel from point A to point B at the reduced speed must be equal to the scheduled time.

Therefore, we can set up the following equation:

x = 1.24x - 10

Solving this equation will give us the value of x, which represents the time it would have taken the bus to travel from point A to point B at the original speed.

Let's solve the equation:

x = 1.24x - 10

0.24x = 10

x = 10 / 0.24

x ≈ 41.67

So, it would have taken the bus approximately 41.67 units of time to travel from point A to point B at the original speed.

Now, let's calculate the duration of the forced stop:

1. The bus traveled from point A to point B at the original speed for approximately 41.67 units of time. 2. On the return trip, the bus increased its speed by 25%. 3. Therefore, the bus would have taken 0.75 * 41.67 units of time to travel from point B to point A.

To find the duration of the forced stop, we subtract the time it took for the return trip from the time it took for the original trip:

41.67 - 0.75 * 41.67

Calculating this expression gives us the duration of the forced stop.

Let's calculate it:

41.67 - 0.75 * 41.67 ≈ 10.42

Therefore, the duration of the forced stop was approximately 10.42 units of time.

Please note that the units of time are not specified in the given information, so we cannot determine the exact duration in minutes or any other specific unit.